AP Physics 1easymcq1 pt
A constant force of 50 N is applied to a 10 kg box, moving it a distance of 5.0 m along a horizontal surface. If the box was initially at rest, what is its final kinetic energy?
A.D) 1000 J
B.C) 500 J
C.A) 50 J
D.B) 250 J
Using the work-energy theorem, the work done on the object equals its change in kinetic energy. Work = force × distance = 50 N × 5.0 m = 250 J. Since the object started from rest, this work equals its final kinetic energy. Option A would be correct if the distance was only 1 m. Option C would result from using 100 N instead of 50 N. Option D would be correct if the mass was 20 kg instead of 10 kg.
DB) 250 J
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