A 0.2 kg ball is thrown upward with an initial speed of 15 m/s. What is the maximum height reached by the ball?

Core Concept

This is a conservation of energy problem. The initial kinetic energy (½mv₀²) converts to gravitational potential energy (mgh) at the maximum height. Setting them equal: ½mv₀² = mgh. The mass cancels out, giving h = v₀²/(2g) = 15²/(2 × 9.8) = 225/19.6 = 11.5 m. Option A is incorrect because it uses v₀/g instead of v₀²/(2g). Option C is incorrect because it uses v₀²/g instead of v₀²/(2g). Option D is incorrect because it uses v₀² instead of v₀²/(2g).