AP Chemistryhardmcq1 pt

The Henderson-Hasselbalch equation is:

A.pH = -log[H⁺]

B.pH = pKa + log([base]/[acid])

C.Ka = [H⁺][A⁻]/[HA]

D.pOH = 14 - pH

Explanation

Core Concept

The Henderson-Hasselbalch equation pH = pKa + log([A⁻]/[HA]) is used to calculate the pH of a buffer solution, where [A⁻] is the conjugate base concentration and [HA] is the weak acid concentration.

Correct Answer

BpH = pKa + log([base]/[acid])

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