AP Chemistryhardmcq1 pt
The solubility product (Ksp) of AgCl is 1.8 × 10⁻¹⁰. The molar solubility of AgCl is:
A.9.0 × 10⁻¹¹ M
B.1.8 × 10⁻¹⁰ M
C.1.3 × 10⁻⁵ M
D.3.2 × 10⁻²⁰ M
Explanation
Core Concept
Ksp = [Ag⁺][Cl⁻]. If s = molar solubility, then Ksp = s². s = √(1.8 × 10⁻¹⁰) = √(18 × 10⁻¹¹) = √18 × 10⁻⁵·⁵ ≈ 4.24 × 10⁻⁶... Actually, s = √(1.8 × 10⁻¹⁰) = 1.34 × 10⁻⁵ M.
Correct Answer
C1.3 × 10⁻⁵ M
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