AP Chemistrymediummcq1 pt
The combustion of methane: CH4 + 2O2 yields CO2 + 2H2O. Given delta Hf of CO2 = -393.5 kJ/mol, H2O = -285.8 kJ/mol, CH4 = -74.8 kJ/mol, what is delta H for the reaction?
A.-890.3 kJ
B.-754.2 kJ
C.-502.5 kJ
D.-604.3 kJ
Delta H = sum(delta Hf products) - sum(delta Hf reactants) = [(-393.5) + 2(-285.8)] - [(-74.8) + 2(0)] = -965.1 + 74.8 = -890.3 kJ.
A-890.3 kJ
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