AP Calculus ABhardmcq1 pt

∫ sin(3x) dx =

A.3cos(3x) + C
B.-cos(3x) + C
C.-⅓cos(3x) + C
D.⅓cos(3x) + C

Explanation

Core Concept

Using u-substitution (u = 3x, du = 3dx): ∫sin(3x)dx = ⅓∫sin(u)du = -⅓cos(u) + C = -⅓cos(3x) + C.

Correct Answer

C-⅓cos(3x) + C

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