AP Calculus ABhardmcq1 pt
∫ sin(3x) dx =
A.3cos(3x) + C
B.-cos(3x) + C
C.-⅓cos(3x) + C
D.⅓cos(3x) + C
Using u-substitution (u = 3x, du = 3dx): ∫sin(3x)dx = ⅓∫sin(u)du = -⅓cos(u) + C = -⅓cos(3x) + C.
C-⅓cos(3x) + C
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