AP Chemistrymediummcq1 pt
Aluminum sulfate dissolves as Al2(SO4)3(s) -> 2 Al3+(aq) + 3 SO4^2-(aq). What is the total molar concentration of ALL dissolved ions in 0.10 M Al2(SO4)3(aq)?
A.0.20 M
B.0.30 M
C.0.10 M
D.0.50 M
Explanation
Core Concept
Each formula unit releases five dissolved ions in total: two aluminum cations and three sulfate anions. Multiplying the formal concentration by five gives 0.10 M times 5, which equals 0.50 M overall. Checking separately, 0.20 M Al3+ plus 0.30 M SO4^2- sums to the same total. Colligative effects and conductivity depend on this summed particle concentration rather than the label concentration.
Correct Answer
D0.50 M
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