AP Chemistrymediummcq1 pt
What is the pH of 0.100 M acetic acid? (Ka = 1.8 × 10⁻⁵)
A.2.87
B.1.00
C.4.74
D.5.87
ICE table with x neglect: Ka = x²/0.100 gives x = √(1.8 × 10⁻⁶) = 1.34 × 10⁻³ M, pH = 2.87. The 5% rule (1.3% ionization) validates the shortcut.
A2.87
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