AP Chemistryeasymcq1 pt
What is the Kb of the acetate ion if Ka of acetic acid is 1.8 × 10⁻⁵?
A.5.6 × 10⁻¹⁰
B.1.8 × 10⁻⁵
C.5.6 × 10⁴
D.1.0 × 10⁻¹⁴
Kb = Kw/Ka = 1.0 × 10⁻¹⁴ ÷ 1.8 × 10⁻⁵ = 5.6 × 10⁻¹⁰. Conjugate pairs share this inverse relationship.
A5.6 × 10⁻¹⁰
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